(1/3)t^3=(27/t)

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Solution for (1/3)t^3=(27/t) equation:


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

(1/3)*t^3 = 27/t // - 27/t

(1/3)*t^3-(27/t) = 0

(1/3)*t^3-27*t^-1 = 0

1/3*t^3-27*t^-1 = 0

(1/3*t^4-27*t^0)/(t^1) = 0 // * t^2

t^1*(1/3*t^4-27*t^0) = 0

t^1

(1/3)*t^4-27 = 0

(1/3)*t^4-27 = 0 // * 0

{ 1, -1, 3, -3, 9, -9, 27, -27, 81, -81 }

1

t = 1

t^4-81 = -80

1

-1

t = -1

t^4-81 = -80

-1

3

t = 3

t^4-81 = 0

3

t-3

t^3+3*t^2+9*t+27

t^4-81

t-3

3*t^3-t^4

3*t^3-81

9*t^2-3*t^3

9*t^2-81

27*t-9*t^2

27*t-81

81-27*t

0

t^3+3*t^2+9*t+27 = 0

{ 1, -1, 3, -3, 9, -9, 27, -27 }

1

t = 1

t^3+3*t^2+9*t+27 = 40

1

-1

t = -1

t^3+3*t^2+9*t+27 = 20

-1

3

t = 3

t^3+3*t^2+9*t+27 = 108

3

-3

t = -3

t^3+3*t^2+9*t+27 = 0

-3

t+3

t^2+9

t^3+3*t^2+9*t+27

t+3

-t^3-3*t^2

9*t+27

-9*t-27

0

t^2+9 = 0

DELTA = 0^2-(1*4*9)

DELTA = -36

DELTA < 0

t in { 3, -3}

t in { 3, -3 }

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